tag:blogger.com,1999:blog-9343908973310261032012-02-15T22:51:02.563-08:00Enhance your skill in tangency drawing. Find the center of arc and draw arc with unknown radius.Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.comBlogger201100tag:blogger.com,1999:blog-934390897331026103.post-67622798017608535622008-06-03T17:59:00.000-07:002009-08-04T00:06:03.731-07:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SE0yK9Hw2OI/AAAAAAAAAF4/dRzWiYZW49g/s1600-h/tangency19.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SE0yK9Hw2OI/AAAAAAAAAF4/dRzWiYZW49g/s400/tangency19.png" alt="" id="BLOGGER_PHOTO_ID_5209875507724736738" border="0" /></a><span style="font-family:arial;">Figure shows template </span><span style="font-size:100%;"><span style="font-family:arial;">ABCDEFG.<br /></span></span><span style="font-size:100%;"><span style="font-family:arial;">Points </span></span><span style="font-size:100%;"><span style="font-family:arial;">A, B, C, D, E, F and G</span></span><span style="font-size:100%;"><span style="font-family:arial;"> are tangent points. CD is a tangent line.<br />Draw the template in full size.<br /><br />1. Measure the distance between O and S<br /><br /></span></span><span style=";font-family:Arial;font-size:100%;" >Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><br /><br /><span style="font-size:100%;"><span style="font-family:arial;"></span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-6762279801760853562?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com5tag:blogger.com,1999:blog-934390897331026103.post-75304495895584346892008-06-02T15:52:00.001-07:002008-12-11T21:02:38.492-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SER5zaFfNbI/AAAAAAAAAFo/Vkl1yhEqjys/s1600-h/tangency17.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SER5zaFfNbI/AAAAAAAAAFo/Vkl1yhEqjys/s400/tangency17.png" alt="" id="BLOGGER_PHOTO_ID_5207420993229764018" border="0" /></a><br /><span style="font-size:100%;"><span style="font-family:arial;">Figure shows a template ABCDEFG.<br />Points B, C, D, E, F and G are tangent points. FE is a tangent line.<br />Draw the template in full size.<br /><br />1. Measure the radius of Rx<br /><br /></span></span><span style=";font-family:Arial;font-size:100%;" >Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-7530449589558434689?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com1tag:blogger.com,1999:blog-934390897331026103.post-37976576176094465042008-06-01T01:19:00.000-07:002008-12-11T21:02:38.633-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SER34aFfNaI/AAAAAAAAAFg/m5fW6vgwFok/s1600-h/tangency16a.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SER34aFfNaI/AAAAAAAAAFg/m5fW6vgwFok/s400/tangency16a.png" alt="" id="BLOGGER_PHOTO_ID_5207418880105854370" border="0" /></a><br /><br /><span style="font-size:100%;"><span style="font-family:arial;">Figure shows a template ABCDEFGHI.<br />Points B, C, D, E, F, G , H and I are tangent points. FE is a tangent line.<br />A is the vertex point of semi parabola and BC is an quadrant of ellipse.<br />Draw the template in full size.<br /><br />1. Measure the length of EF<br /><br /></span></span><span style=";font-family:Arial;font-size:100%;" >Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><br /><span style="font-size:100%;"><span style="font-family:arial;"><br /><br /></span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-3797657617609446504?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com1tag:blogger.com,1999:blog-934390897331026103.post-35315775289464929762008-05-27T21:45:00.001-07:002008-12-11T21:02:38.905-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDzk_kvHg9I/AAAAAAAAAFQ/xT7L-CbWycA/s1600-h/tangency15.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDzk_kvHg9I/AAAAAAAAAFQ/xT7L-CbWycA/s400/tangency15.png" alt="" id="BLOGGER_PHOTO_ID_5205287050177643474" border="0" /></a><br /><span style="font-size:100%;"><span style="font-family:arial;">Figure 4 shows a ABCDEFGH template. </span> <span style="font-family:arial;"> Redraw the template shown in full size using geometrical construction methods.</span> <span style="font-family:arial;"> AB is a quadrant of an ellipse with O as the center of ellipse.</span></span><br /><br /><span style="font-family:arial;">1. Measure the length of EF,<br />2. What is the distance between A and B?<br /><br /></span><span style=";font-family:Arial;font-size:100%;" >Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-3531577528946492976?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com3tag:blogger.com,1999:blog-934390897331026103.post-62857890635106958292008-05-27T21:27:00.001-07:002008-12-11T21:02:39.051-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDzfWUvHg7I/AAAAAAAAAFA/kp5DQHLNj5k/s1600-h/tangency14.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDzfWUvHg7I/AAAAAAAAAFA/kp5DQHLNj5k/s400/tangency14.png" alt="" id="BLOGGER_PHOTO_ID_5205280843949900722" border="0" /></a><br /><span style="font-family:arial;"> Figure shows a template. A, B, C, D, E, F and G are points of tangency. BC is a tangent line. O is the centre points of the ellipse. Draw the template in full size.<br /><br />1. Measure the radius of Rx,<br />2. Measure the length of line BC.<br /><br /></span><span style=";font-family:Arial;font-size:100%;" >Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-6285789063510695829?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-3013636515600823542008-05-27T20:41:00.000-07:002008-12-11T21:02:39.223-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDzWo0vHg6I/AAAAAAAAAE4/1HFiwmo_AzY/s1600-h/tips05.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDzWo0vHg6I/AAAAAAAAAE4/1HFiwmo_AzY/s400/tips05.png" alt="" id="BLOGGER_PHOTO_ID_5205271266172830626" border="0" /></a><br /><br /><span style="font-size:100%;"><span style="font-family:arial;"><span style="font-weight: bold;">How to draw an arc in touch externally and touch through a given point<br /><br /></span>1. Draw a perpendicular line PR,<br />2. Draw a parallel line OA,<br />3. Draw line AP intersecting at K,<br />4. Draw line OK intersecting at S,<br />5. Centered at S, draw arc through P and K.<br /><span style="font-weight: bold;"></span></span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-301363651560082354?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com1tag:blogger.com,1999:blog-934390897331026103.post-28594902022353123722008-05-27T20:20:00.000-07:002008-12-11T21:02:39.468-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDzShkvHg4I/AAAAAAAAAEo/5Ug7MsnbSX8/s1600-h/tips04.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDzShkvHg4I/AAAAAAAAAEo/5Ug7MsnbSX8/s400/tips04.png" alt="" id="BLOGGER_PHOTO_ID_5205266743572267906" border="0" /></a><br /><br /><br /><span style="font-family:arial;"><span style="font-size:100%;"><span style="font-weight: bold;">How to draw an arc in touch internally and through a given point<br /><br /></span>1. Draw line PR and bisect it.<br />2. Draw straight line RO to intersect at S.<br />3. Centered at S, draw an arc through P and R.<br /><span style="font-weight: bold;"></span></span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-2859490202235312372?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-53649137461691730562008-05-26T18:23:00.000-07:002008-12-11T21:02:39.743-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDtqG0vHg0I/AAAAAAAAAEE/Xtv-fYb4eEc/s1600-h/tangency13.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDtqG0vHg0I/AAAAAAAAAEE/Xtv-fYb4eEc/s400/tangency13.png" alt="" id="BLOGGER_PHOTO_ID_5204870459824767810" border="0" /></a><br /><br /><br /><br /><span style="font-size:100%;"><span style="font-family:arial;">Figure shows a template ABCDEFGHP.</span> <span style="font-family:arial;">Points B, C, D, E, F, G and H are tangent points. AP and CD are tangent lines.</span> <span style="font-family:arial;">P is the centre point of an quadrant of ellipse. Distance between H and O is </span> <span style="font-family:arial;">78mm.</span><span style="font-family:arial;"> Draw the template in full size.<br /><br /></span></span><span style=";font-family:Arial;font-size:100%;" >1. What is the distance between points P and Q?<br />2. What is the diameter of Rx?<br /><br />Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-5364913746169173056?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com1tag:blogger.com,1999:blog-934390897331026103.post-9629518103216608362008-05-26T17:56:00.000-07:002008-12-11T21:02:39.939-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDteikvHgwI/AAAAAAAAADk/aylUMBkSCLA/s1600-h/tangency12.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDteikvHgwI/AAAAAAAAADk/aylUMBkSCLA/s400/tangency12.png" alt="" id="BLOGGER_PHOTO_ID_5204857742426604290" border="0" /></a><span style=";font-family:arial;font-size:100%;" ><br /></span><span style=";font-family:arial;font-size:100%;" >Figure shows a template ABCDEFG.<br />Points A, B, C, D and G are tangent point. CD is a tangent line.<br />F is a vertex of half parabola EF.<br />Draw the template in full size.<br /><br /></span><span style="color: rgb(51, 0, 51);font-family:georgia;font-size:100%;" >1. What is the length of CD?<br />2. What is the diameter of Rx?<br /><br />Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-962951810321660836?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-80958388681110978332008-05-26T17:34:00.000-07:002008-12-11T21:02:40.141-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDtaQEvHgvI/AAAAAAAAADc/_BH7tHYPl2c/s1600-h/tangency11.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDtaQEvHgvI/AAAAAAAAADc/_BH7tHYPl2c/s400/tangency11.png" alt="" id="BLOGGER_PHOTO_ID_5204853026552513266" border="0" /></a><br /><span style="font-family: arial;font-size:100%;" >Figure shows a template ABCDEF. A, C, D, E and F are points of<br /></span><span style="font-family: arial;font-family:arial;font-size:100%;" >tangency. EF is a tangent line. A is the vertex of the half parabola.<br />Draw the template in full size</span><span style="font-family: arial;font-size:100%;" >.<br /><br /></span><span style="font-family: arial;font-family:georgia;font-size:100%;" >1. What is the distance between points O and Q?<br />2. What is the diameter of Rx?<br /><br />Mail your answer to: <a href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a>.<br />The correct answer will get the participation certificate.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-8095838868111097833?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-34951879944603896282008-05-25T20:46:00.001-07:002008-12-11T21:02:40.589-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDo1gEvHguI/AAAAAAAAADU/30RJx9DGdYM/s1600-h/tangency10.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDo1gEvHguI/AAAAAAAAADU/30RJx9DGdYM/s400/tangency10.png" alt="" id="BLOGGER_PHOTO_ID_5204531144523481826" border="0" /></a><br /><span style="font-size:100%;"><span style="font-family: arial;">Redraw the template with full scale. A, B, C, D, E, F and G are points of tangency. AG is straight line.</span><br /><br /><span style="font-family: arial;">1. What is the distance between points P and Q?</span><br /><span style="font-family: arial;">2. What is the diameter of Rx?</span><br /><br /><span style="font-family: arial;">Mail your answer to: </span><a style="font-family: arial;" href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a><span style="font-family: arial;">.</span><br /><span style="font-family: arial;">The correct answer will get the participation certificate.</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-3495187994460389628?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-11504597903436412992008-05-25T19:42:00.000-07:002008-12-11T21:02:40.773-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDolTkvHgsI/AAAAAAAAADE/lDJbmiHuqM8/s1600-h/tangency09.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDolTkvHgsI/AAAAAAAAADE/lDJbmiHuqM8/s400/tangency09.png" alt="" id="BLOGGER_PHOTO_ID_5204513337589072578" border="0" /></a><br /><span style="font-size:100%;"><span style="font-family: arial;">Redraw the template with full scale. A, B, C, D, E, F and G are points of tangency. AB and GF are straight line. Q is centre of quarter ellipse.</span><br /><br /><span style="font-family: arial;">1. What is the distance between points P and Q?</span><br /><span style="font-family: arial;">2. What is the diameter of Rx?</span><br /><br /><span style="font-family: arial;">Mail your answer to: </span><a style="font-family: arial;" href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a><span style="font-family: arial;">.</span><br /><span style="font-family: arial;">The correct answer will get the participation certificate.</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-1150459790343641299?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-50680429358914398622008-05-25T18:39:00.001-07:002008-12-11T21:02:41.013-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDoVeUvHgqI/AAAAAAAAAC0/0nWK3l5RKHQ/s1600-h/tangency08.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_0osNeIsh_Eg/SDoVeUvHgqI/AAAAAAAAAC0/0nWK3l5RKHQ/s400/tangency08.png" alt="" id="BLOGGER_PHOTO_ID_5204495930086621858" border="0" /></a><br /><br /><span style="font-size:100%;"><span style="font-family: arial;">Redraw the template with full scale. A, B, C, D, and E are points of tangency. AB is a straight line.</span><br /><br /><span style="font-family: arial;">1. What is the radius of Rx?</span><br /><span style="font-family: arial;">2. What is the length of AB?</span><br /><br /><span style="font-family: arial;">Mail your answer to: </span><a style="font-family: arial;" href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a><span style="font-family: arial;">.</span><br /><span style="font-family: arial;">The correct answer will get the participation certificate.</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-5068042935891439862?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-8457505719494203072008-05-25T18:19:00.001-07:002008-12-11T21:02:41.234-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDoQa0vHgoI/AAAAAAAAACk/3uo4ThCOliY/s1600-h/tangency07.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SDoQa0vHgoI/AAAAAAAAACk/3uo4ThCOliY/s400/tangency07.png" alt="" id="BLOGGER_PHOTO_ID_5204490372398940802" border="0" /></a><span style="font-size:100%;"><span style="font-family: arial;">Redraw the template with full scale. A, B, C, D, E and F are points of tangency. AB is a straight line.</span><br /><br /><span style="font-family: arial;">1. What is the radius of Rx?</span><br /><span style="font-family: arial;">2. What is the length of AB?</span><br /><br /><span style="font-family: arial;">Mail your answer to: </span><a style="font-family: arial;" href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a><span style="font-family: arial;">.</span><br /><span style="font-family: arial;">The correct answer will get the participation certificate.</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-845750571949420307?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-2767503924963042442008-05-25T18:05:00.000-07:002008-12-11T21:02:41.383-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDoNqkvHgnI/AAAAAAAAACc/gr1gah7IMN0/s1600-h/tangency06.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDoNqkvHgnI/AAAAAAAAACc/gr1gah7IMN0/s400/tangency06.png" alt="" id="BLOGGER_PHOTO_ID_5204487344446997106" border="0" /></a><br /><span style="font-size:100%;"><span style="font-family: arial;">Redraw the template with full scale. C, D, E, F, G and H are points of tangency. Lines AH and FG touch the circles. OB is the axis of the symmetrical parabolic.</span><br /><br /><span style="font-family: arial;">1. What is the length of AH and FG?</span><br /><span style="font-family: arial;">2. What is the distance between O and P?</span><br /><br /><br /><span style="font-family: arial;">Mail your answer to: </span><a style="font-family: arial;" href="mailto:noh4568@yahoo.com">noh4568@yahoo.com</a><span style="font-family: arial;">.</span><br /><span style="font-family: arial;">The correct answer will get the participation certificate.</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-276750392496304244?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-48791765483440535422008-05-20T18:49:00.001-07:002008-12-11T21:02:41.550-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDOBvYlX2PI/AAAAAAAAAB0/DR4cCveAbL8/s1600-h/tangency05.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://2.bp.blogspot.com/_0osNeIsh_Eg/SDOBvYlX2PI/AAAAAAAAAB0/DR4cCveAbL8/s400/tangency05.png" alt="" id="BLOGGER_PHOTO_ID_5202644645596092658" border="0" /></a><br /><span style="font-weight: bold; font-family: arial;font-size:100%;" >Draw the template, and measure the radius of Rx.<br /><br /></span><span style="font-family: arial;font-size:100%;" ><a href="mailto:noh4568@yahoo.com">Email for the answer</a></span><span style="font-weight: bold;"><br /></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-4879176548344053542?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-78688458819342996302008-05-20T18:31:00.000-07:002008-12-11T21:02:41.985-08:00<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDN-Z4lX2LI/AAAAAAAAABU/Jcgc3hE9Grs/s1600-h/tangency04a.png"><img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SDN-Z4lX2LI/AAAAAAAAABU/Jcgc3hE9Grs/s400/tangency04a.png" alt="" id="BLOGGER_PHOTO_ID_5202640977694021810" border="0" /></a><br /><span style="font-weight: bold;">Draw this template and measure the radius of Rx.</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-7868845881934299630?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com1tag:blogger.com,1999:blog-934390897331026103.post-24257454772349326292008-05-17T04:44:00.000-07:002008-12-11T21:02:42.188-08:00<a href="http://3.bp.blogspot.com/_0osNeIsh_Eg/SC7Fg4lX2GI/AAAAAAAAAAs/MO15te61oOk/s1600-h/tangency03.png"><img style="margin: 0px 10px 10px 0px; float: left;" id="BLOGGER_PHOTO_ID_5201311788395124834" alt="" src="http://3.bp.blogspot.com/_0osNeIsh_Eg/SC7Fg4lX2GI/AAAAAAAAAAs/MO15te61oOk/s400/tangency03.png" border="0" /></a><br /><div><span style="font-weight: bold;">How to draw a line internally tangency between two circles.</span><br /><br />- Draw an arc through center of two circle.<br />- Draw another arc with radius of R59 plus R39 and intersect at D.<br />- Draw line AD.<br />- E and F are the point of tangency.<br /><br /></div><br /><div></div><br /><div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-2425745477234932629?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-45617808340439791802008-05-17T04:07:00.000-07:002008-12-11T21:02:42.366-08:00<a href="http://4.bp.blogspot.com/_0osNeIsh_Eg/SC684IlX2FI/AAAAAAAAAAk/cQ57i47c0ZI/s1600-h/tangency02.png"><img style="margin: 0px 10px 10px 0px; float: left;" id="BLOGGER_PHOTO_ID_5201302292222433362" alt="" src="http://4.bp.blogspot.com/_0osNeIsh_Eg/SC684IlX2FI/AAAAAAAAAAk/cQ57i47c0ZI/s400/tangency02.png" border="0" /></a><br /><div><span style="font-weight: bold;">How to draw a line tangency to two circle.</span><br /><br />- Draw line between two center.<br />- Draw arc through these center.<br />- Draw circle with R59-R39 to intersect<br /> the arc at D.<br />- Draw line AD and project until E.<br />- Draw parallel line AE and BF.<br />- EF is line of tangency between two<br /> circle.<br /></div><br /><div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-4561780834043979180?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0tag:blogger.com,1999:blog-934390897331026103.post-15355924509826313582008-05-17T01:41:00.000-07:002008-12-11T21:02:42.900-08:00<a href="http://2.bp.blogspot.com/_0osNeIsh_Eg/SC7I9olX2II/AAAAAAAAAA8/ZwB-WVC0l_U/s1600-h/tangency01.png"><img style="margin: 0px 10px 10px 0px; float: left;" id="BLOGGER_PHOTO_ID_5201315580851247234" alt="" src="http://2.bp.blogspot.com/_0osNeIsh_Eg/SC7I9olX2II/AAAAAAAAAA8/ZwB-WVC0l_U/s400/tangency01.png" border="0" /></a><br /><div><br /><div><br /><div><br /><div><span style="font-weight: bold;">How to draw a line tangency to a circle.</span> </div><div> </div><div>- Draw a line from point P to the </div><div> centre of the circle, R.</div><div>- Draw an arc through point P and R.</div><div>- N is the point of tangency.</div><div>- Draw line PN.</div><br /><div></div><br /><div></div><br /><br /><div></div><br /><br /><div></div><div></div><div></div></div></div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/934390897331026103-1535592450982631358?l=engineering-drawing.blogspot.com' alt='' /></div>Mohd Noh Sariphttp://www.blogger.com/profile/17237962438262153003noreply@blogger.com0